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Unit 7 Review: Solving Quadratic Equations
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What methods of solving quadratic equations have we learned so far?
Square root, factoring, completing the square, quadratic formula, zero product property
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What are the two solution(s) to the equation: (x - 3)(2x + 18) = 0
x = 3, x = -9
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Use the quadratic formula to solve the equation: x² + 9x + 18 = 0
x = -3, x = -6
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What are the two solution(s) to the equation: (x - 5)² = 0
x = 5
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What are the two solutions to the equation: 432 = 3x²
x = -12, x = 12
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What are the two solutions to the equation: (x+ 1)² = 144
x = 11, x = -13
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Rewrite the equation into factored form: x² + 35x - 36
(x + 36)(x - 1)
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Use the quadratic formula to solve the equation: x² - 4x = 21
x = -3, x = 7
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Use the quadratic formula to solve the equation: 3x² - 6x - 9 = 0
x = -1, x = 3
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Identify the a, b, and c values of the equation: x² = 121
a = 1, b = 0, c = 121
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How do we write a quadratic equation in standard form?
ax² + bx + c
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What are the two solution(s) to the equation: (7 - x)(x + 4) = 0
x = 7, x = -4
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Rewrite the equation into factored form: x² + 6x + 9
(x + 3)(x + 3)
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Identify the a, b, and c values of the equation: -x² + 9x + 18 = 0
a = -1, b = 9, c = 18
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Rewrite the equation into factored form: x² + 13x + 30
(x + 3)(x + 10)
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Use the quadratic formula to solve the equation: x² + 11x + 24 = 0
x = -8, x = -3
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Use the quadratic formula to solve the equation: x² +3x - 10 = 0
x = -5, x = 2
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Rewrite the equation into factored form: x² - 7x + 12
(x - 4)(x - 3)
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Use the quadratic formula to solve the equation: 4x² + 20x + 25 = 0
x = - 2.5
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BAAMBOOZLE DOUBLE!!! Recite the quadratic formula >:)
-b plus or minus the square root of b² minus 4ac divided by 2a
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What are the two solutions to the equation: x² + 4 = 404
x = -20, x = 20
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What are the two solutions to the equation: (x - 5)² - 30 = 70
x = 5, x = -15
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Use the quadratic formula to solve the equation: 2x² - 7x = 15
x = -1.5, x = 5
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Square roots have what type of solutions?
Positive and negative
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