Unit 7 Review: Solving Quadratic Equations | Baamboozle - Baamboozle

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Solving Quadratic Equations

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#algebra 1 #factoring #quadratic formula #square root #Quadratic Equations #completing the square

What are the two solutions to the equation: x² + 4 = 404

x = -20, x = 20

What are the two solutions to the equation: 432 = 3x²

x = -12, x = 12

What are the two solutions to the equation: (x+ 1)² = 144

x = 11, x = -13

What are the two solutions to the equation: (x - 5)² - 30 = 70

x = 5, x = -15

What are the two solution(s) to the equation: (x - 5)² = 0

x = 5

What are the two solution(s) to the equation: (7 - x)(x + 4) = 0

x = 7, x = -4

What are the two solution(s) to the equation: (x - 3)(2x + 18) = 0

x = 3, x = -9

Rewrite the equation into factored form: x² - 7x + 12

(x - 4)(x - 3)

Rewrite the equation into factored form: x² + 6x + 9

(x + 3)(x + 3)

Rewrite the equation into factored form: x² + 13x + 30

(x + 3)(x + 10)

Rewrite the equation into factored form: x² + 35x - 36

(x + 36)(x - 1)

Use the quadratic formula to solve the equation: x² + 9x + 18 = 0

x = -3, x = -6

Identify the a, b, and c values of the equation: -x² + 9x + 18 = 0

a = -1, b = 9, c = 18

Identify the a, b, and c values of the equation: x² = 121

a = 1, b = 0, c = 121

Use the quadratic formula to solve the equation: x² +3x - 10 = 0

x = -5, x = 2

Use the quadratic formula to solve the equation: 2x² - 7x = 15

x = -1.5, x = 5