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Unit 7 Review: Solving Quadratic Equations
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Use the quadratic formula to solve the equation: x² - 4x = 21
x = -3, x = 7
BAAMBOOZLE DOUBLE!!! Recite the quadratic formula >:)
-b plus or minus the square root of b² minus 4ac divided by 2a
How do we write a quadratic equation in standard form?
ax² + bx + c
Square roots have what type of solutions?
Positive and negative
What methods of solving quadratic equations have we learned so far?
Square root, factoring, completing the square, quadratic formula, zero product property
Use the quadratic formula to solve the equation: 4x² + 20x + 25 = 0
x = - 2.5
Use the quadratic formula to solve the equation: x² + 11x + 24 = 0
x = -8, x = -3
Use the quadratic formula to solve the equation: 3x² - 6x - 9 = 0
x = -1, x = 3
Use the quadratic formula to solve the equation: 2x² - 7x = 15
x = -1.5, x = 5
Use the quadratic formula to solve the equation: x² +3x - 10 = 0
x = -5, x = 2
Identify the a, b, and c values of the equation: x² = 121
a = 1, b = 0, c = 121
Identify the a, b, and c values of the equation: -x² + 9x + 18 = 0
a = -1, b = 9, c = 18
Use the quadratic formula to solve the equation: x² + 9x + 18 = 0
x = -3, x = -6
Rewrite the equation into factored form: x² + 35x - 36
(x + 36)(x - 1)
Rewrite the equation into factored form: x² + 13x + 30
(x + 3)(x + 10)
Rewrite the equation into factored form: x² + 6x + 9
(x + 3)(x + 3)
Rewrite the equation into factored form: x² - 7x + 12
(x - 4)(x - 3)
What are the two solution(s) to the equation: (x - 3)(2x + 18) = 0
x = 3, x = -9
What are the two solution(s) to the equation: (7 - x)(x + 4) = 0
x = 7, x = -4
What are the two solution(s) to the equation: (x - 5)² = 0
x = 5
What are the two solutions to the equation: (x - 5)² - 30 = 70
x = 5, x = -15
What are the two solutions to the equation: (x+ 1)² = 144
x = 11, x = -13
What are the two solutions to the equation: 432 = 3x²
x = -12, x = 12
What are the two solutions to the equation: x² + 4 = 404
x = -20, x = 20