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Pre-algebra | 2.5 Exercises (Practice B)

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  • Mr. Harding sold 100 shares of stock at $14 per share. He had a loss of $6 per share. What did Mr. Harding pay for each share of the stock?
    $14 + $6 = $20 per share
  • f + 15 = -16
    f = -31
  • 14 + m = -10
    m = -24
  • e/7 = 8
    e = -56
  • s/-9 = 9
    s = -81
  • y - 5 = -4
    y = 1
  • q + 6 = -2
    q = -8
  • -3b = 36
    b = -12
  • 13 = x - 15
    x = 28
  • -63 = -9s
    s = 7
  • d/5 = -7
    d = -35
  • -100 = -4u
    u = 25
  • -6 = 21 - n
    n = 27
  • x = 15 - 31
    x = -16
  • -75 = 3v
    v = -25
  • n - 9 = -14
    n = -5
  • g - 19 = -21
    g = -2
  • The temperature in Minnesota was -8 °F one day. This was 12 degrees less than the temperature in Indiana on the same day. What was the temperature in Indiana?
    -8 + 12 = 4 degrees F
  • 9h = -36
    h = -4
  • 0 = w + 4
    w = -4
  • c/4 = -20
    c = -80
  • LaShonda bought 20 shares of stock for $175. She sold the stock for a total profit of $25. What was the selling price of each share of stock?
    $175 + $25 = $200; $200/20 = $10 for each share of stock
  • 12 = w/4
    w = 48
  • p + 18 = 14
    p = -4