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QUADRATIC FUNCTION
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When a>0, so the graph of the function will have .... point.
minimum
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What is the co-ordinate of y-intercept of: y = x^2 + x - 6
( 0, -6)
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Andi just throw up a ball and used the function h(t) = 8t - 2t^2 (h = height in m, t = time in s). What is highest point of the ball?
8 m
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From the graph below, we know that the quadratic function has .... ( value of a and D)
a > 0 ( because the graph has a minimum point), D > 0 (because there are two co - ordinate of x - intercept)
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What is determinant used for? And what is the formula of D?
To find the x - intercept of quadratic function. D = b^2 - 4ac
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From the graph, we know that the quadratic function has ... (value of a and D)
a > 0 (because the graph has a minimum point), D < 0 (because there is no x - intercept)
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What is the minimum point of: y = x^2 - 4x - 21
x = 2 , y =- 25 (2,-25)
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What is the co-ordinate of y-intercept of: y = x^2 - 4
( 0, -4 )
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What is the maximum point of: y = -x^2 + 2x + 6
x = 1, y = 7 (1, 7)
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What is the co-ordinate of x-intercept of y = x^2 - 2x - 24
x = -4 or x = 6
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When a<0, so the graph of the function will have .... point
maximum
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Okay!
What is the value of a, b, and c of : y = -x^2+3x-4
-1, 3, -4
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What is the co-ordinate of x-intercept of y = x^2 + 3x - 18
x = 3 or x = -6
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What is the formula to get a maximum or minimum of some quadratic function?
find the axis of symmetry: x = -b / 2a then do the subtitution into the quadratic equation
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From the graph below, we know that the quadratic function has .... ( value of a and D)
a < 0 ( because the graph has a maximum point), D = 0 (because there is one co - ordinate of x - intercept)
Oops!
Okay!
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