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IM 1 Mid-chapter 1 Review

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  • (zk)/f = n ; solve for z
    z = (nf)/k
  • 10(4x +2) = 5(x + 15)
    x = 11/7
  • -(2x +4) = 8
    x = -6
  • 3x + 7 = 4x + 7
    x = 0
  • -8 = -5t + 9 +11t
    t = -17/6
  • 5x - 3 >= 2x + 96
    x >= 33
  • a/c = b ; solve for c
    c = a/b
  • 3x + 4 = 3x + 5
    no solution
  • 18x + 2 < 4(2x + 6)
    x < 2.2
  • 2f(2) + 9(3) = 4f +27
    infinitely many solutions
  • 4x + 20 > -x
    x > -4
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