Unit 7 Review: Solving Quadratic Equations | Baamboozle - Baamboozle

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Use the quadratic formula to solve the equation: x² + 9x + 18 = 0

x = -3, x = -6

Use the quadratic formula to solve the equation: x² - 4x = 21

x = -3, x = 7

Use the quadratic formula to solve the equation: 4x² + 20x + 25 = 0

x = - 2.5

What methods of solving quadratic equations have we learned so far?

Square root, factoring, completing the square, quadratic formula, zero product property

Rewrite the equation into factored form: x² + 35x - 36

(x + 36)(x - 1)

BAAMBOOZLE DOUBLE!!! Recite the quadratic formula >:)

-b plus or minus the square root of b² minus 4ac divided by 2a

Rewrite the equation into factored form: x² + 13x + 30

(x + 3)(x + 10)

Use the quadratic formula to solve the equation: x² +3x - 10 = 0

x = -5, x = 2

How do we write a quadratic equation in standard form?

ax² + bx + c

Rewrite the equation into factored form: x² + 6x + 9

(x + 3)(x + 3)

Use the quadratic formula to solve the equation: 2x² - 7x = 15

x = -1.5, x = 5

Square roots have what type of solutions?

Positive and negative

Rewrite the equation into factored form: x² - 7x + 12

(x - 4)(x - 3)

Use the quadratic formula to solve the equation: x² + 11x + 24 = 0

x = -8, x = -3

What are the two solutions to the equation: (x - 5)² - 30 = 70

x = 5, x = -15

What are the two solutions to the equation: 432 = 3x²

x = -12, x = 12

What are the two solution(s) to the equation: (7 - x)(x + 4) = 0

x = 7, x = -4

What are the two solutions to the equation: x² + 4 = 404

x = -20, x = 20

Use the quadratic formula to solve the equation: 3x² - 6x - 9 = 0

x = -1, x = 3

What are the two solutions to the equation: (x+ 1)² = 144

x = 11, x = -13

Identify the a, b, and c values of the equation: -x² + 9x + 18 = 0

a = -1, b = 9, c = 18

What are the two solution(s) to the equation: (x - 3)(2x + 18) = 0

x = 3, x = -9

Identify the a, b, and c values of the equation: x² = 121

a = 1, b = 0, c = 121

What are the two solution(s) to the equation: (x - 5)² = 0

x = 5