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Gas Laws (Boyle and Charles)

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  • In the question: "Calculate the decrease in temperature when 2.00 L at 21.0 °C is compressed to 1.00 L." What is 1.00 L?
    Final volume (V2)
  • T1 = 300 K, V2 = 10 L, T2 = 600 K, V1 = ____.
    5 L
  • Convert 300 Kelvin to Celcuis.
    27 Celcius
  • If the pressure and amount of gas are constant, the relationship between temperature and volume is...
    Directly proportional
  • What is the standard pressure in kPa?
    101.3 kPa
  • P1 = 5 atm, V1 = 5 L, V2 = 2.5 L, P2=____
    10 atm
  • In defining Charles' Law, the volume of the gas is directly propotional to ______.
    Temperature
  • Conver 2 atmosphere to kilopascals.
    202.6
  • P1 = 2.5 atm, V1 = 2.5 L, P2 = 1.25 atm, V2=____.
    5 L
  • In defining Charles' Law the quantities which remain constant are...
    pressure and moles
  • STP stands for...
    Standard Temperature and pressure
  • If the pressure of the gas remains constant but the temperature is increased, the volume will _____.
    Increase
  • In the question: "Convert 338 L at 63.0 atm to its new volume at STP" What is the variable required to find?
    Final Volume (V2)
  • What is the Standard temperature?
    0 C
  • If the pressure and amount of gas are constant, the relationship between temperature and volume is _______.
    directly proportional
  • Molecules of gasses are close to each other when...
    heated
    cooled
    compressed
    expanded
  • Convert the pressure 0.840 atm to torr.
    638 torr
  • In the question: "The pressure inside the rigid container at 20.0 °C was 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 36.9 °C?" What is the variable required to find?
    Final Pressure (P2)
  • If the reading of the pressure is equal to 570 mm Hg, what is it in atmosphere?
    0.75 atm
  • Convert the pressure 0.575 atm to torr.
    437 torr
  • In the question: "Find the final volume if 60.0 mL of gas is cooled from 33.0 °C to 5.00 °C?" What is 5 °C
    Final Temperature (T2)
  • V1 = 1 L, V2 = 3 L, T2 = 819 K, T1 = ____.
    273 K
  • In defining Boyle's Law, the variables that remain constant are...
    Temperature and moles
  • Convert 320 Kelvin to degrees Celcius.
    47 C
  • Which of the following expressions relates to the Kelvin and Celsius temperature scales?
    A.) K = 273 + °C
    B.) K= - 273 + °C
    D.) K = 273°C
    C.) °C + 273 K
  • The boiling point of water in kelvin scale is ______.
    373 K
  • Convert 650 mL to cubic decimeter (dm3)
    0.65 dm3
  • In defining Boyle's Law, pressure is inversely proportional to what variable?
    Volume
  • In the question "Calculate the decrease in temperature when 2.00 L at 21.0 °C is compressed to 1.00 L." What is 2.00 L?
    Initial volume (V1)
  • The freezing point of water in kelvin scale is ______.
    273 K
  • Convert 6.7 decimeter cube (dm3) into milliliters.
    6700 mL