Study

U-tube Redox

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  • What happens to MnO₄⁻ ions?
    MnO₄⁻ is reduced to Mn²⁺.
  • What happens to Fe²⁺ ions?
    Fe²⁺ is oxidised to Fe³⁺.
  • Which substance acts as the oxidising agent?
    KMnO₄ / Acidified Potassium manganate(VII) solution
  • Which substance acts as the reducing agent?
    FeSO₄ / Iron(II) sulphate
  • State the half-equation for reduction of MnO₄⁻ to Mn²⁺ in acidic medium.
    MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
  • This reaction occurs in a U-tube cell. State the direction of electron flow.
    From Fe²⁺ (anode) to MnO₄⁻ (cathode).
  • State the half-equation for oxidation of Fe²⁺ to Fe³⁺.
    Fe²⁺ → Fe³⁺ + e
  • Why is potassium manganate(VII) solution used in this experiment?
    It is a strong oxidising agent
  • State the change in oxidation number of Fe in this reaction.
    Fe: +2 to +3
  • Why must KMnO₄ be in acidic condition to act as an oxidising agent?
    MnO₄⁻ only reduces in acidic medium.
  • In this reaction, which substance loses electrons?
    Iron(II)