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2.3 DC Circuits
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Mae dau wrthydd, 4 ohm a 6 ohm, wedi'u cysylltu mewn cyfres. Mae'r cyfuniad hwn wedi'i gysylltu mewn cylched gyfochrog â gwrthydd 12 ohm. Beth yw cyfanswm yr gwrthiant?
Mae'r cyfuniad cyfres yn rhoi gwrthiant o 4 + 6 = 10 ohm. Cyfanswm gwrthiant paralel yw 1 / R_cyf = 1 / 10 + 1 / 12. Felly, R_cyf = 5.45 ohm.
What is the relationship between emf, internal resistance, and the terminal voltage in a circuit? Explain using the equation V = E - Ir.
The terminal voltage V is the emf E minus the voltage drop across the internal resistance Ir. As the current increases, the voltage drop increases, reducing the
In a potential divider circuit with a thermistor, how does the output voltage (across the thermistor) change as the temperature increases, assuming the thermistor's resistance decreases with temperature?
As the temperature increases, the thermistor's resistance decreases, which causes the output voltage across the thermistor to decrease.
A battery has an emf of 18 V and an internal resistance of 1 ohm. If a 5-ohm resistor is connected across the battery, what is the current in the circuit, and what is the potential difference across the 5-ohm resistor?
Total resistance = 5 + 1 = 6 ohms. Current I = 18 V / 6 ohms = 3 A. Voltage across 5-ohm resistor = 3 A * 5 ohms = 15 V.
Mewn cylched gyfres, mae dau wrthydd o 8 ohm a 12 ohm wedi'u cysylltu â batri 24 V. Beth yw’r gwahaniaeth potensial ar draws pob gwrthydd?
Cyfanswm y gwrthiant = 8 + 12 = 20 ohm. Y cerrynt = 24 V / 20 ohm = 1.2 A. Gwahaniaeth potensial ar draws y gwrthydd 8 ohm = 1.2 A × 8 ohm = 9.6 V, ac ar draws
Explain how the internal resistance of a battery affects the emf and the voltage delivered to an external circuit.
The emf represents the total energy per charge that the battery can supply, but the internal resistance causes a voltage drop within the battery. The voltage de
Two resistors, 6 ohms and 12 ohms, are connected in parallel. What is the total resistance of the combination?
1 / R_total = 1 / 6 + 1 / 12. R_total = 4 ohms.
Mae gan fatri GEM (EMF) o 24 V a gwrthiant mewnol o 2 ohm. Os yw gwrthydd 4 ohm wedi’i gysylltu ar draws y batri, beth yw’r cerrynt yn y gylched, a beth yw’r gwahaniaeth potensial ar draws y gwrthydd 4 ohm?
Cyfanswm y gwrthiant = 4 + 2 = 6 ohm. Y cerrynt I = 24 V / 6 ohm = 4 A. Y gwahaniaeth potensial ar draws y gwrthydd 4 ohm = 4 A × 4 ohm = 16 V.
Mae cylched cyfochrog â chyfanswm cerrynt o 25 A. Os yw'r cerrynt trwy'r gangen gyntaf yn 10 A a’r ail gangen yn 7 A, beth yw’r cerrynt yn y drydedd gangen?
8 A. Mae cadwraeth gwefr yn datgan bod cyfanswm y cerrynt sy'n mynd i mewn i gymal yn hafal i gyfanswm y cerrynt sy’n gadael, felly 25 A - (10 A + 7 A) = 8 A.
A battery has an emf of 12 V and an internal resistance of 1 ohm. If a current of 2 A is drawn from the battery, what is the potential difference across the terminals of the battery?
10 V. Using the formula V = E - Ir, V = 12 V - (2 A * 1 ohm) = 10 V.
Why is the unit of emf the same as the unit of potential difference?
Both emf and potential difference are measured in volts because they both represent the energy transferred per unit charge (1 volt = 1 joule per coulomb).
Diffiniwch gem (emf) ffynhonnell ac eglurwch sut mae’n wahanol i’r gwahaniaeth potensial ar draws llwyth.
Ateb: Mae’r emf (grym electromotif) yn egni a ddarperir fesul uned wefr gan y ffynhonnell
Os oes dau wrthwydd o 5 ohms ac 10 ohms wedi'u cysylltu mewn paralel ar draws batri 12 V, beth yw'r gwahaniaeth potensial ar draws pob gwrthydd?
12 V. Mewn cylchedau paralel, mae'r gwahaniaeth potensial drwy bob cydran yn hafal i foltedd y ffynhonnell.
In a series circuit with a 12 V battery and two resistors, explain how energy is conserved.
The total energy supplied by the battery is used up by the resistors. The voltage across each resistor adds up to the total voltage of the battery.
In a parallel circuit, if the total current entering the junction is 10 A, and the currents through two branches are 4 A and 3 A, what is the current through the third branch?
Conservation of charge states that the sum of currents entering a junction equals the sum of currents leaving.
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