find the probability that the shuttle would launch safely under similar conditions.
P=(0.977)^6 = 0.87
4.6 - Exercise #1
(.98)^20 = .668
4.6 - Exercise #8
(.90)^20 = .1216
4.7 - Example
9*23*26*23*10*10*10 = 123,786,000
4.7 - Exercise #2
20*19*10*10*10*10*10*10*4=1,520,000,000
4.7 - Exercise #5
6! = 720
4.7 - Exercise #10
75 P 10 = 3x10^18
4.8 - Example
49 C 6 = 13,983,816
4.8 - Exercise #2
52 C 5 = 2,598,960
4.8 - Exercise #11
.0750
