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8.1-8.3 review

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    geometric mean theorem, converse of pythagorean theorem and special right triangles
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  • Given <JOM =90, OK is the altitude,. If JK=12, KM=5, find OK
    2√15
  •  15
  • Given <JOM =90, OK is the altitude. If OK= 3 √5 and JK=9, find KM
    5
  •  15
  • Given <JOM =90, OK is the altitude, if JO=3 √2 and JK=3, find JM
    6
  •  15
  • Given <JOM =90, OK is the altitude. If KM=5 and JK=6, find OM
    √55
  •  15
  • 1) Find a 2) Find ab 3) Find a+b+c
    1) 9, 2) 54 3) 15+6√3
  •  25
  • Find the length of the diagonal of a square with perimeter 12cm
    3 √2
  •  15
  • In the following problem, a and b are legs, c is the hypotenuse. a=1, b=1/3, find c
    5/3
  •  10
  • In the following problem, a and b are legs, c is the hypotenuse. a=8√5, b=16, find c
    24
  •  5
  • In the following problem, a and b are legs, c is the hypotenuse. a=0.7, c=2.5, find b
    2.4
  •  5
  • In the following problem, a and b are legs, c is the hypotenuse. a=150, c=170. Find b
    80
  •  5
  • In the following problem, a and b are legs, c is the hypotenuse. c=500, a=200, find b
    100 √21
  •  5
  • In the following problem, a and b are legs, c is the hypotenuse. b=15, c=39. find a
    36
  •  5
  • In the following problem, a and b are legs, c is the hypotenuse. b=5√7, c=13√7. find a
    12√7
  •  5
  • In the following problem, a and b are legs, c is the hypotenuse. a=33, c=44, find b
    11√7
  •  5
  • Find the missing sides of the triangle
    x=2√3, y=4√3
  •  25
  • Find the missing sides
    4√2
  •  20