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Year 8 Pythagoras Theorem
Game Code: 3147769
English
24
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Pythagoras Theorem Review
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What is the Pythagoras theorem
c2 = a2 + b2
5
The Pythagoras theorem only applies to what type of triangle?
Right-angle triangle
5
Is [4, 5, 9] a Pythagorean triple? Show your working out with a clear answer
[a2 + b2 = 42 + 52 = 41] and [c2 = = 81]. 41 is not the same as 81, therefore, it is not a Pythagorean triple.
15
Is [8, 15, 17] a Pythagorean triple? Show your working out with a clear answer
[a2 + b2 = 64 + 225 = 289] and [c2 = 289]. 289 is the same as 289, therefore, it is a Pythagorean triple.
15
Is [10, 12, 20] a Pythagorean triple? Show your working out with a clear answer
[a2 + b2 = 100 + 144 = 244] and [c2 = 400]. 244 is not the same as 400, therefore, it is not a Pythagorean triple.
15
Classify this triangle as right, obtuse, or acute angled triangle. Show working out to prove it.
[c2 = 64] is greater than [a2 + b2 = 52]. Therefore, it is an obtuse angle trignale
15
This triangle is isosceles. Write Pythagoras’ theorem using the given pronumerals and simplify.
(Pythagoras = a2 + b2 = c2) a and b are represented by x, therefore, x2 + x2 = c2. Simplified = 2x squared = c2
15
Classify this triangle as right, obtuse, or acute angled triangle. Show working out to prove it.
[c2 = 100] is equal to [a2 + b2 = 100]. Therefore, it is a right angle triangle
15
Classify this triangle as right, obtuse, or acute angled triangle. Show working out to prove it.
[c2 = 36] is greater than [a2 + b2 = 34]. Therefore, it is an obtuse angle triangle
15
Classify this triangle as right, obtuse, or acute angled triangle. Show working out to prove it.
[c2 = 64] is less than [a2 + b2 = 85]. Therefore, it is an acute angle triangle
15
The hypotenuse is always opposite to the:
right angle.
5
A rectangular wall is 5 m wide and 4 m high. Find the length of a diagonal brace correct to the nearest cm
[a2 + b2 = 25+ 16 = 41]. Estimated square root of 41 = 6.40 cm.
15
Explain why this working out to find the hypotenuse (c) is incorrect.
You cannot add 3 and 4 together like that. You must square them separately, add them together, and then square root the sum to find c.
10
Explain why this working out to find the hypotenuse (c) is incorrect.
You must indicate in the last line that c = square root of 29. Otherwise, you've indicated the answer as the value of c2.
10
Find the length of the hypotenuse of these right-angled triangles, correct to two decimal places.
Square root of [a2 + b2 = 85] = 9.22
15
Find the length of the hypotenuse of these right-angled triangles, correct to two decimal places.
Square root of [a2 + b2 = 32] = 5.66
15
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