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Geometry (2023) - Unit 11 Test Review (Circles)

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    Unit 11 Test Review (Circles)
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  • In circle Z, the m∠ABC = 57°. Find the measure of minor arc AC.
    2 * 57 = 114°
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  • Given: Circle S and the measure of ∠RST = 88°. What is the measure of ∠RUT?
    88/2=44°
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  • The circumference of circle J is 72π. What is the length of minor arc NK? Leave your answer in terms of π.
    (145/360)*72π = 29π
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  • A section of a circular sign is shown. What is the area of this section of the sign? Round your answer to the nearest tenth.
    (92/360)(π(12)^2)=115.6
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  • What is the equation of the circle shown on the graph?
    (x+1)^2 + (y-2)^2 = 25
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  • A circle has a diameter with endpoints (−2,−3) and (6, -3). What is the equation of the circle?
    (x-2)^2 + (y+3)^2 = 16
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  • The equation of a circle is given. Determine the center of the circle and the length of the diameter.
    Center: (1, -5) Diameter: 7*2=14
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  • Jack started writing the equation of circle O as follows. He knows that a point with coordinates (2, 10) lies on circle O. What number should Jack place in the blank to finish writing the equation?
    (2+4)^2 + (10-6)^2 = 52
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  • Circle G has a center at (7, 5) and a diameter of 12 units. Which point lies on circle G?
    b) (13, 5)
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  • Which one of the following sets of numbers could represent the three sides of a right triangle?
    c) 9, 40, 41
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  • What is the sum of the exterior angles of a convex polygon with 45 sides?
    360 (EXTERIOR ANGLES ALWAYS SUM TO 360)
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  • Determine the proportional relationship that would correctly solve for the arc length of the shaded sector x.
    b
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  • If the area of a sector of a circle is 29π m^2 and the measure of its intercepted arc is 76°, what is the length of the radius of the circle?
    a
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  • A student is using the Pythagorean theorem to derive the equation of a circle with a center (-2, 7) and a radius of 9. What is the equation of the circle?
    (x+2)^2 + (y-7)^2 = 81
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  • A circle has a diameter with endpoints (5,−6) and (6, -7). What is the center of the circle?
    midpoint((5, -6),(6, -7)) = (5.5, -6.5)
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