If AD/DB = AE/EC, what can we conclude? A) DE ⟂ BC B) DE ∥ BC C) DE = BC D) Triangle ABC is isosceles

The Theorem is called the Basic Proportionality Theorem.

In a triangle, if a line divides the sides proportionally, it must be: A) Perpendicular to the base B) Parallel to the base C) Tangent to the base D) None of these

In △ABC, if DE ∥ BC, then which of the following is true? A) AD = DB B) AE + EC = AD + DB C) AD/DB = AE/EC D) AD × DB = AE × EC

The converse of the theorem proves a line is parallel if the sides are divided proportionally.

The Triangle Proportionality Theorem only applies when: A) The line passes through the midpoint of one side B) The line is parallel to one side C) The triangle is right-angled D) All sides are equal

If a line is parallel to one side of a triangle, it divides the other two sides: A) Equally B) Perpendicularly C) Proportionally D) Unequally

The theorem helps prove which geometric property? A) Area of triangles B) Proportional sides C) Congruence of triangles D) Perimeter of polygons

The theorem works for any triangle shape (scalene, isosceles, or equilateral).

If DE ∥ BC, AD = 2, DB = 6, and AE = 3, find EC. A) 8 B) 9 C) 12 D) 7