A 600N man is playing on a seesaw with son who has a weight of 180N. If the child is sitting 2 meters away, how far will the man have to sit to balance the seesaw?
0.6 m
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15
Find the moment of inertia for A wooden hoop has a mass of 2.5 kg and a radius of 15 cm with an axis of rotation through the center. I=mr2
0.056 kg.m2
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15
Find the moment of inertia for A small concrete cylinder has a mass of 25 kg and a radius of 14 cm with an axis of rotation through the center (I=(1/2)mr2)
0.25 kgm2
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15
Where will be the center of mass of a uniform rod lies ?
At its middle point
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monster
Reset all scores!
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rocket
Go to first place!
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gift
Win 25 points!
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banana
Go to last place!
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eraser
Reset score!
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gift
Win 20 points!
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rocket
Go to first place!
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baam
Lose 20 points!
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15
Find the moment of inertia for A piece of cardboard has a length of 32 cm, a width of 22 cm and a mass of 92 g with an axis of rotation through the center. I=(1/12) m(l2+w2)
1.3Ã10â3 kgm2 or 0.013 kgm2
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15
Salma, who has a mass of 42 kg, and Josh, who has a mass of 45 kg, are trying to balance a seesaw. Salma's position is shown in the diagram. How far should Josh sit from the pivot point to balance Salma?
0.75 m
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15
A bolt is to be tightened with a torque of 8.0 Nm. If you have a wrench that is 0.35 m long, what is the least amount of force you must exert?
23 N
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15
Barbara exerts a force of 48 N on the outer edge of a door that is 76 cm wide. What is the magnitude of torque if the force is perpendicular to the door?
36 N.m
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15
Which vehicle is more stable?
The black car, because it has a wide base and low center of mass.
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15
The figure below shows a wheel rotating about the axle. Consider, a=10.0 cm b=25.0 cm and the counterclockwise torque to be positive. Torque due to 9 N force is equal to ____
â2.25 N.m
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15
The figure below shows a wheel rotating about the axl . Consider, a=10.0 cm b=25.0 cm and the counterclockwise torque to be positive. Torque due to 10 N force is equal to ____
â2.50 N.m
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15
A disc of mass 2 kg and radius 20 cm is free rotate about an axis through its centre and perpendicular to the disc. If a force of 25 N is applied tangentially to the disc, then the angular acceleration is......(Note, for a disk. I=(1/2)mr2)