Geometriyadan Savollar | Baamboozle - Baamboozle

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25

Savol: Har bir tomoni 6 sm bo‘lgan muntazam olti burchakning yuzini toping.

54 ildiz osti 3

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15

Savol: Trapetsiyaning asoslari 14 sm va 8 sm, yon tomonlari 5 sm va 7 sm. Agar balandligi 6 sm bo‘lsa, yuzasini toping.

66 sm (kvadrat)

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20

Savol: Rombning tomoni 10 sm, unga tushirilgan balandlik 6 sm ga teng. Romb yuzini toping.

60 sm 2 (kvadrat)

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15

Har qanday a burchak uchun qaysi formula o'rinli ?

sin2a+cos2a=1

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15

Savol: Har bir tomoni 10 sm bo‘lgan muntazam beshburchak (pentagon)ning yuzasi taxminan qancha bo‘ladi?

172 sm 2 (kvadrat)

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10

Savol: Trapetsiyaning asoslari 12 sm va 6 sm. Yuzasi 90 sm². Trapetsiyaning balandligini toping

10 sm

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trap

No points!

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magnet

Take 25 points!

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rocket

Go to first place!

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baam

Lose 20 points!

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seesaw

Swap points!

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gift

Win 20 points!

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rocket

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banana

Go to last place!

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25

Savol: Rombning diagonallari biri ikkinchisidan 4 sm uzun. Agar rombning yuzasi 120 sm² bo‘lsa, diagonallarni toping.

d1=13.62 sm ; d2=17.62sm

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25

Savol: Muntazam to‘rt burchak (kvadrat)ning yuzasi 144 sm². Har bir tomonining uzunligini toping.

12 sm

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